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f(x) = 0 ⇔ (a-2)x + 5 = 0
z treści zadania:
f(-1) = 0 ⇔ (a-2)(-1) + 5 = 0
-a + 2 + 5 = 0
-a = -7
a = 7
Odp. Miejscem zerowym funkcji f(x) jest liczba -1 dla a=7.
f(-1) = 0
(a - 2) * (-1) + 5 = 0
-a + 2 + 5 = 0
-a + 7 = 0
-a = -7/:(-1)
a = 7