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Jedno rozwiazanie gdy delta =0
Δ=(m+3)²-4(4m-4)=m²+6m+9-16m+16=m²-10m+25
m²-10m+25=0
(m-5)²=0⇒|m-5|=0⇒m=5
ODP. Dla m=5 rownanie ma jedno rozwiazanie