<AOC + <BOD = <AEC + <DEB
65° + 140° = <AEC + <AEC
2.<AEC = 205°
<AEC = 102,5°
<AEC + <BEC = 180°
102,5° + <BEC = 180°
<BEC = 77,5°
<AED + <BEC = <AOD + <BOC
<AED + <AED = 32° + 122°
2.<AED = 154°
<AED = <BEC = 77°
<AOB + <BOC + <DOC + <AOD = 360°
<AOB + 122° + <DOC + 32° = 360°
<AOB + <DOC = 206°
<DEC + <AEB = <DOC + <AOB
<DEC + <DEC = 206°
<DEC = 206°/2
<DEC = <AEB = 103°
<KOL = <KQL
<KQL = 60°
<KOL = 60°
<KPL + <KLP + <LKP = 180°
<KPL + 90° + 60° = 180°
<KPL = 30°
<AED = ½ (<AOD -<BOC)
<AED = ½ (94° -40°)
<AED = ½ × 54°
<AED = 27°
Jawaban:
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Nomor 1
<AOC + <BOD = <AEC + <DEB
65° + 140° = <AEC + <AEC
2.<AEC = 205°
<AEC = 102,5°
<AEC + <BEC = 180°
102,5° + <BEC = 180°
<BEC = 77,5°
Nomor 2
<AED + <BEC = <AOD + <BOC
<AED + <AED = 32° + 122°
2.<AED = 154°
<AED = <BEC = 77°
<AOB + <BOC + <DOC + <AOD = 360°
<AOB + 122° + <DOC + 32° = 360°
<AOB + <DOC = 206°
<DEC + <AEB = <DOC + <AOB
<DEC + <DEC = 206°
<DEC = 206°/2
<DEC = <AEB = 103°
Nomor 3
<KOL = <KQL
<KQL = 60°
<KOL = 60°
<KPL + <KLP + <LKP = 180°
<KPL + 90° + 60° = 180°
<KPL = 30°
Nomor 4
<AED = ½ (<AOD -<BOC)
<AED = ½ (94° -40°)
<AED = ½ × 54°
<AED = 27°
Jawaban:
Jawaban ada di Foto
Penjelasan dengan langkah-langkah:
semoga membantu