dany jest wielomian W(x)=x^5-6x^4+3x^3+2x^2+ax o ktorym wiadomo ze W(-2)=8 WYZNACZ liczbe a
^ do potegi
8=-32-6*16-3*8+2*4-2a
8=-32-96-24+8-2a
2a= -152 /:2
a= -76
W(-2)=(-2)⁵-6×(-2)⁴+3×(-2)³+2×(-2)²-2a=8
-32-96-24+8-2a=8
2a=-152
a=-152;2
a=-76
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8=-32-6*16-3*8+2*4-2a
8=-32-96-24+8-2a
2a= -152 /:2
a= -76
W(-2)=(-2)⁵-6×(-2)⁴+3×(-2)³+2×(-2)²-2a=8
-32-96-24+8-2a=8
2a=-152
a=-152;2
a=-76