dany jest wielomian w (x) . oblicz w (-1), w (2) gdy: d) w(x) = √2x4+2√2x3-3√2x2-4√2
w(x) = √2x⁴+2√2x³-3√2x²-4√2
w(-1) = √2·(-1)⁴ + 2√2·(-1)³-3√2·(-1)²-4√2 = √2-2√2-3√2-4√2 =-8√2
w(2) = √2·2⁴+2√2·2³-3√2·2²-4√2 = √2·16+2√2·8 -3√2·4-4√2 =
= 16√2+16√2-12√2-4√2 = 16√2
w(-1) =4√-2-4√2
w(2)=8-4√2
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w(x) = √2x⁴+2√2x³-3√2x²-4√2
w(-1) = √2·(-1)⁴ + 2√2·(-1)³-3√2·(-1)²-4√2 = √2-2√2-3√2-4√2 =-8√2
w(2) = √2·2⁴+2√2·2³-3√2·2²-4√2 = √2·16+2√2·8 -3√2·4-4√2 =
= 16√2+16√2-12√2-4√2 = 16√2
w(-1) =4√-2-4√2
w(2)=8-4√2