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B(-3;-2)
AB= pierwiastek z :(-3-1)²+(-2-1)²=√16+9=√25=5
obcinek AB ma 5
|CA|= 4
A²+B²=C²
3²+4²=C²
9+16=C²
25=C²/√
5=C
Odcinek |AB| ma długość 5