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a) a×3+6=9 i
a×1+6=3
b=9-3a i
a +9-3a=3
-2a=3-9
-2a=-6
a=3
b)
9-3×3=9-9=0
f(x)=3x
f(9)=3×9=27
B)
f(4)=5 i
f(6)=9
a×4+b=5 i
a×6+b+9
b=5-4a i
6a+5-4a=9
2a=9-5
2a=4
a=2
b=5-4×2
b=5-8=-3
f(x)=2x-3
f(9)=2×9-3=18-3=15
C)
f(2)=-1 i
f(3)=-2
a×2+b=-1 i
a×3+b=-2
b=-1-2a i
3a-1-2a=-2
3a-2a=-2+1
a=-1
b=-1-2(-1)=-1+2=1
f(x)=-x+1
f(9)=-9+1=-8
D)
f(-2)=0 i
f(-6)=2
a×(-2)+b=0 i
a×(-6)+b=2
b=2a
-6a+2a=2
-4a=2
a=-½
b=2×a=2×(-½)=-1
f(x)=-½x-1
f(9)=-½×9-1=-4,5-1=-5,5