Oblicz stężenie molowe wodnego r-ru NaOH o stężeniu 35% i gęstości 1,38g/cm3.
Cm=Cp x d/100% x M
M: 23+16+1=40g/mol
Cm=35% x 1,38g/cm3 / 100% x 40g/mol
Cm=0,35 x 1,38 / 40
Cm= 0,012075g/cm3=12,075g/dm3
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Cm=Cp x d/100% x M
M: 23+16+1=40g/mol
Cm=35% x 1,38g/cm3 / 100% x 40g/mol
Cm=0,35 x 1,38 / 40
Cm= 0,012075g/cm3=12,075g/dm3