Dosypano 42 gramy soli do 210 cm3 jej 20% roztworu o gestosci 1,15 g/cm3. podaj stezenie procentowe otrzymanego roztworu?
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d=m/V
m= 1,15*210
m=241,5g roztworu
Cp=ms/mr * 100%
0,2=ms/241,5
ms=48,3g soli
Cp=(48,3+42)/(241,5+42)*100%
Cp=32%