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V1 - obj. benzenu, d1 = 0,8737g/cm3.....gęst. benzenu
V2 - obj. toluenu d2 = 0,8623g/cm3.....gęst. toluenu
szukane: % zaw.benzenu w mieszaninie
V1/V2 = 1/4.........V1 = m1/d1.......V2 = m2/d2
V1/V2 = [m1/d1]*[d2/m2] = [m1/m2][d2/d1] = 1/4 = 0,25
m1/m2 = 0,25*d1/d2 = 0,25*0,8737/0,8623 = 0,253
m2/m1 = 3,9525
m2 = 3,9525 m1
%wag.benzenu = m1*100%/[m1 + 3,9525m1] = 20,2%
................pozdrawiam