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2CxHy + 10O2 ---> 6CO2 + H2O (Setarakan O di kanan)
2CxHy + 10O2 ---> 6CO2 + 8H2O
2x=6 2y=16
x=3 y=8 jadi C3H8
2.. Mr molekul= m.22,4/v = 14 x 22,4/5,6= 14 x 4= 56
Mr molekul=(Mr empiris)n
56=(12+2(1))n
56=14n
n=4 ....jadi (CH2)4= C4H8