13 dan 14][ 2 bidang miring lucin sin α = 3/5 tan θ = 4/3 → sin θ = 4/5 m₁ = 5 kg m₂ = 2 kg g = 10 m/s² T = __? a = __?
Percepatan Tinjau sistem benda keseluruhan ΣF = Σm a m₁g sin α - m₂g sin θ = (m₁ + m₂) a 5•10 • 4/5 - 2•10 • 3/5 = (5+2) • a 40 - 12 = 7 a 28 = 7 a a = 4 m/s² ← jwb
Gaya tegangan tali Tinjau benda m₂ T - m₂g sin θ = m₂ a T - 2•10 • 3/5 = 2 • 4 T - 12 = 8 T = 20 N ← jwb
Verified answer
12][ ??13 dan 14][
2 bidang miring lucin
sin α = 3/5
tan θ = 4/3 → sin θ = 4/5
m₁ = 5 kg
m₂ = 2 kg
g = 10 m/s²
T = __?
a = __?
Percepatan
Tinjau sistem benda keseluruhan
ΣF = Σm a
m₁g sin α - m₂g sin θ = (m₁ + m₂) a
5•10 • 4/5 - 2•10 • 3/5 = (5+2) • a
40 - 12 = 7 a
28 = 7 a
a = 4 m/s² ← jwb
Gaya tegangan tali
Tinjau benda m₂
T - m₂g sin θ = m₂ a
T - 2•10 • 3/5 = 2 • 4
T - 12 = 8
T = 20 N ← jwb