(a-b)c/b = de |*b oczywiście b≠0
ac-bc=bde |+bc
ac=b(de+c) |÷ca=[b(de+c)]/ c (a-b)c/b = de |÷e[(a-b)c/be=d
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(a-b)c/b = de |*b oczywiście b≠0
ac-bc=bde |+bc
ac=b(de+c) |÷c
a=[b(de+c)]/ c
(a-b)c/b = de |÷e
[(a-b)c/be=d