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f´(x)=2*(2x+1)^(2-1) * (2x+1)´
f´(x)=2*(2x+1)* [(2x)´+1´]
f´(x)=2*(2x+1)* [2x´+0]
f´(x)=2*(2x+1)* [2(1)]
f´(x)=2*(2x+1)* [2]
f´(x)=4*(2x+1)