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A. 1 lim n + 3 / 2 = ∞ → diverge
n → ∞ 2
B. U¹ = 1 + 3 /2 = 2
U² = 2 + 3 /2 = 2,5 = 5/2
U³ = 3 + 3 /2 = 6/2 = 3
C. n ≥ 1 → n + 3/ 2 ≥ 2
(NOTA: los números ¹ ² ³ van abajo de la U, solo que no le puse allí pues porque no se podía)