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1,3y = -3,9x + 2,6 | :1,3
y = -3x + 2
b)½x-¼y+5/8=0
-¼y = -½x -⅝ |:(-¼)
y = 2x + 2½
c)3⅓x+6⅔=-1⅔y
1⅔y = -3⅓x - 6⅔ |: 1⅔
y = (-10/3x : 5/3) - (20/3 : 5/3)
y = -2x - 4
Pozdrawiam.! ;*
a) 3,9x-2,6+1,3y=0
1,3y=-3,9x+2,6
y=-3x+2
b)½x-¼y+5/8=0
1/4y=1/2x+5/8
y=2x+5/2
c)3⅓x+6⅔=-1⅔y
5/3y=-10/3x-20/3
y=-2x-4
1,3y=-3,9x+2,6 /:1,3
y=-3x+2
b) 1/2x-1/4y+5/8=0
-1/4y=-1/2x-5/8 /:(-1/4)
y=2x+5/2
c) 3⅓x+6⅔=-1⅔y
-5/3y=10/3x+20/3 /:(-5/3)
y=-2x-4