?
.... = [3^(1/2)]^log₃ 16 = 3^(1/2 * log₃ 16) = 3^log₃ 16^(1/2) = 3^log₃ √16 = 3^log₃ 4 = 4
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Litterarum radices amarae sunt, fructus iucundiores
Pozdrawiam :)
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.... = [3^(1/2)]^log₃ 16 = 3^(1/2 * log₃ 16) = 3^log₃ 16^(1/2) = 3^log₃ √16 = 3^log₃ 4 = 4
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Litterarum radices amarae sunt, fructus iucundiores
Pozdrawiam :)