Question

Potęga o wykładniku naturalnym!!!
a) 4×(-0,5)²+6×(-⅔)²=
b) (½)²+(-0,8)÷(-⁴/₅)=
c) ⅔+[(-¹/₃)²+(-¹/₃)²]÷¹/₃=
A i wyniki maja wyjść w a)3²/₃ w b)1¹/₄ a w c)1¹/₃

Answer 1

A) 4*(0,5)² + 6* (-2/3)² = 4*0,25 + 6*4/9 = 1+8/3 = 1+ 2 2/3= 3+2/3

b) (1/2)² + (-0,8) ÷ (-4/5) = (1/4) + 1= 1 1/4

c) 2/3 + [ (-1/3)² + (-1/3)²] : 1/3 = 2/3 + [1/9 + 1/9] : ⅓ = ⅔ + 2/9 : ⅓ = ⅔ + 2/9*3/1 = ⅔ + ⅔ = 4/3 = 1 ⅓