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por propiedad sabemos que la
(suma de antecedentes) / (suma de consecuentes) = k
por ello:
a+b-c = 35
(a+b-c) / (6+3-4) = k
35 / 5 = 7 = k
ahora piden (a+b)
(a+b) / (6+3) = k = 7
(a+b)/ 9 = 7
(a+b) = 7(9)
a + b = 63
Listo XD