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b)(√2 + 4x)(4x - √2) -2(2x - 1/4)² = 4x√2 - 2 + 16x² - 4x√2 =
16x² - 2
c)(√2+a)(a-√2)+(-3√2+2a)² = a√2 - 2 + a² - a√2 = a² - 2
d)(2√2+4x)(4x-2√2)-2(2x-1/4)² = 8x√2 - 8 + 16x² - 8x√2 = 16x² - 8
Ile jest : 2√2 razy 2√2 = 4 * √4 = 4 * 2 = 8
reszta w załączniku :)