August 2018 1 23 Report

me pueden explicar !!?

logaritmos:

loga 2= 1/5 (HALLAR a)

log6 b = 0 (hallar b)

log2/3 b= -3 (hallar b)

log81 b= -1/4 (hallarb)

log(raiz cuadrada de 5) x =6


More Questions From This User See All

Life Enjoy

" Life is not a problem to be solved but a reality to be experienced! "

Get in touch

Social

© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.