August 2018 1 21 Report

me pueden explicar !!?

logaritmos:

loga 2= 1/5 (HALLAR a)

log6 b = 0 (hallar b)

log2/3 b= -3 (hallar b)

log81 b= -1/4 (hallarb)

log(raiz cuadrada de 5) x =6


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