Question

Dany jest wielomian W Oblicz w [-1] W[0] W[1] gdy; W[x]=-1/3xdo 6-1/2xdo3+3xdo2+6 W[x]=3/4xdo7-1/3xdo5+3xdo2+2x

Answer 1

 

 

 

 

;)

Answer 2

W(x) = ( -1/3) x^6 - (1/2) x^3 + 3 x^2 + 6

zatem

W(-1) = ( - 1/3)*1 - ( 1/2)*(-1) + 3*1 + 6 = - 2/6 + 3/6 + 9 =  9  1/6

W(0) = ( -1/3)*0 - (1/2)*0 + 3*0 + 6 = 6

W(1) = ( -1/3)*1 - (1/2)*1 + 3*1 + 6 = - 2/6 - 3/6 + 9 = 9 - 5/6 = 8  1/6

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W(x) = ( 3/4) x^7 - (1/3) x^5 + 3 x^2 + 2 x

zatem

W(-1) = ( 3/4)*( -1) - (1/3)*(-1) + 3*1 + 2*(-1) = - 3/4 + 1/3 + 3 - 2 =

         = - 9/12 + 4/12 + 1 = 1 - 5/12 = 7/12

W( 0) = ( 3/4)*0 - (1/3)*0 + 3*0 + 2*0 = 0

W( 1) = (3/4)*1 - (1/3)*1 + 3*1 + 2*1 = 3/4 - 1/3 + 3 + 2 =

         =  9/12 - 4/12 + 5 = 5/12 + 5 = 5  5/12

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