Oblicz podstawę trapezu .
a=10
b= ?
h=6
P=42
a=?
b=20
h=8
P=120
a=2,4
b= ?
h=4
P=7
a= 6 1/3
b= ?
h= 6
P = 33
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a) P = (a + b) /2 * h
42 = (10 +b) / 2 * 6
b = 4
b ) 120 = (a + 20) / 2 * 8
a = 10
c) 7 = (2,4 + b) / 2 * 4
b = 1,1
d) 33 = (6 + b) / 2 * 6
b = 5