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sinα+sinβ=2sin[(α+β)/2]*cos[(α-β)/2]
sin(3x)+sin(3x+π/2)=√2
2sin[(6x+π/2)/2]*cos(-π/4)=√2
2*sin(3x+π/4)*√2/2=√2
sin(3x+π/4)=1
3x+π/4=π/2 +2kπ, k∈C
3x=π/4+2kπ /:3
x=π/12+2/3kπ