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f'(x)=-1/3*3x²-1/2*2x+6 = -x²-x+6
-x²-x+6=0
Δ=1+4*6=25
x=(1-5)/(-2) = 2 v x=(1+5)/(-2)=-3
Znaki pochodnej
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min max
max=f(2)=-1/3*2³-1/2*2²+6*2+10 = 22-2-8/3 = 20-8/3=52/3=17,333...
KOD 173