" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
sin²α+cos²α=1
cosα=√[1-sin²α]
tgα=sinα/cosα
1/3=sinα/ √[1-sin²α] /²
1/9=sin²α/(1-sin²α)
9sin²α=1-sin²α
10sin²α=1
sin²α=1/10
sinα=√10/10
.........................
cosα=√[1-1/10]=√(9/10)=3√10/10