Oblicz wartos liczbowa wyrazenia.
a) (a⁻²)³ dla a=-1
b) [(a+b)³]⁻¹ dla a=-2,b=4
c) (-ab²/3)⁻² dla a=2,b=-1
d)[(a²)⁻¹]³ dla a=-2
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a) (a⁻²)³ dla a=-1
dla 'a' podstawiamy -1 i podnosimy do -2, wiec wychodzi -1 i potem -1 do 3 co sie rowna -1
Odp.: -1
b) [(a+b)³]⁻¹ dla a=-2,b=4
( -2+4)^3 = 2^3 = 8
8^(-1) = 1/8
Odp.: 1/8
c) (-ab²/3)⁻² dla a=2,b=-1
((-2) * (-1^2)) / 3 = -2/3
(-2/3)^-2 = 9/4
Odp.: 9/4 = 2 i 1/4
d)[(a²)⁻¹]³ dla a=-2
Odp.: -1/64
a)
b)![[(-2+4)^{3}]^{-1}=[(-8+64)]^{-1}=56^{-1}=(\frac{1}{56})^{1}=\frac{1}{56} [(-2+4)^{3}]^{-1}=[(-8+64)]^{-1}=56^{-1}=(\frac{1}{56})^{1}=\frac{1}{56}](https://tex.z-dn.net/?f=%5B%28-2%2B4%29%5E%7B3%7D%5D%5E%7B-1%7D%3D%5B%28-8%2B64%29%5D%5E%7B-1%7D%3D56%5E%7B-1%7D%3D%28%5Cfrac%7B1%7D%7B56%7D%29%5E%7B1%7D%3D%5Cfrac%7B1%7D%7B56%7D)
c)
d)![[(-2^{2})^{-1}]^{3}=[(4)^{-1}]^{3}=[(\frac{1}{4})^{1}]^{3}=(\frac{1}{4})^{3}=\frac{1}{64} [(-2^{2})^{-1}]^{3}=[(4)^{-1}]^{3}=[(\frac{1}{4})^{1}]^{3}=(\frac{1}{4})^{3}=\frac{1}{64}](https://tex.z-dn.net/?f=%5B%28-2%5E%7B2%7D%29%5E%7B-1%7D%5D%5E%7B3%7D%3D%5B%284%29%5E%7B-1%7D%5D%5E%7B3%7D%3D%5B%28%5Cfrac%7B1%7D%7B4%7D%29%5E%7B1%7D%5D%5E%7B3%7D%3D%28%5Cfrac%7B1%7D%7B4%7D%29%5E%7B3%7D%3D%5Cfrac%7B1%7D%7B64%7D)