Question

Prosze pomuzcie mi obliczyc:

a) 2-4+ (4/3)-2+ (2/5)-3 =

b) [ 5 - 3 * (2/5)0 ] -2 =

c) 27-5/3+ (1/16)1/4 =

d) √2 * 41/3 * 8-1/3 =

Dam naj :)

Answer 1

a)      A) 2-4  +  (4/3)-2  +  (2/5)-3= (1/2)4+ (3/4)2 + (5/2)3  =  (1/16) +(9/16) +(125/8)=(10/16)+(250/16)= 260/16 = 65/4  =16,25

b)      B) [5-3*(2/5)0]-2=[(1/5)3  *  1]-2  =[ ( 1/125)]-2=1252=15625

c)       C) 27-5/3  +(1/16) ¼ =(1/27)5/3 +  4√(1/16) =   [3√(1/27)]5 +(1/2)= (1/3)5 + (1/2) =(1/243) + (1/2) = (2/486) +(243/486)=(245/486)

d)      D) √2 * 41/3  *  8-1/3  =21/2 * 2 2/3 * 2 -1 = 2 1/2 +(2/3)  -1 = 2 1/6                                  

m mam nadzieje ze dobrze odczytalam:)

m