Skróć ułamki podaj konieczne założenia
a.x²-4/3x+6
b.25-x²/5+x
c.4x²-9/3-2x
a)
(x^2 - 4)/(3x+6) = (x+2)(x-2)/3(x+2) = (x-2)/3
Z: x =/= -2
b)
(25 - x^2 )/(5+x) = (5+x)(5-x)/(5+x) = 5-x
Z: x =/= -5
c)
(4x^2 - 9)/(3-2x) = -(2x+3)(2x-3)/(2x-3) = -2x-3
Z: 2x-3 =/= 0
x =/=1 1/2
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a)
(x^2 - 4)/(3x+6) = (x+2)(x-2)/3(x+2) = (x-2)/3
Z: x =/= -2
b)
(25 - x^2 )/(5+x) = (5+x)(5-x)/(5+x) = 5-x
Z: x =/= -5
c)
(4x^2 - 9)/(3-2x) = -(2x+3)(2x-3)/(2x-3) = -2x-3
Z: 2x-3 =/= 0
x =/=1 1/2