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-2(y-1)+{-4(y-1)-5[y-2(4-y)+3y]-(y+1)}=2y-(-5-y)
-2y+2+{-4y+4-5y+10(4-y)-15-y-1}=2y+5+y
-2y+2+{-4y+4-5y+40-10y-15-y-1}=3y+5
-2y+2-4y+4-5y+40-10y-15-y-1=3y+5
-2y-4y-5y-10y-y-3y=5-2-4-40+15+1
-25y=-40+15
-25y=-25
y=-25/-25
y=1
solucion
y=1
saludos