Question

Ayuda por favor

(X+1)(x+2)(x-3)=(x-2)(x+1)^2

Answer 1

Solución:

(X+1)(x+2)(x-3)=(x-2)(x+1)^2

(X+1)(x+2)(x-3) - (x-2)(x+1)^2  = 0

factor comun: (x+1):

(x+1)[(x+2)(x-3) - (x-2)(x+1)] = 0

aplicando prop distributiva:

(x+1)(x²-x-6-x²+x+2) = 0

(x+1)(-4) = 0

x+1 = 0

x = -1

Saludos!! Jeizon1L