Zad 1 a) Dane są wielomiany W(x)=2x do 2-x+1 P(x)=-3x do 2+x-2 i Q(x)=3x-1. Wykonaj działania: W(x)*Q(x)-P(x)= [Q(x)]do2 - 3P(x)+2W(x)
b) Wyznacz dziedzinę wyrażenia wymiernego: xdo2-1/2do2+6x+4=
Zad 2 Rozwiąż 2 równania:
a) x+4/x-2=3
b) x-4/2x+4=x+2
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1.
W(x) = 2x^2 - x + 1
P(x) = 3x^2 + x - 2
Q(x) = 3x - 1
W(X) * Q(X) - P(x) = [Q(x)]^2 - 3*P(x) + 2*W(x)
6x^3 - 2x^2 - 3x^2 + x + 3x - 1 - 3x^2 - x + 2 = 9x^2 - 6x + 1 - 9x^2 - 3x + 6 + 4x^2 - 2x + 2
6x^3 - 8x^2 + 3x + 1 = 4x^2 - 11x + 9
6x^3 - 12x^2 + 14x - 8
2.
x + 4/x - 2 = 3 ... / *x
x^2 + 4 - 2x = 3x
x^2 - 5x + 4 = 0
delta = 25 - 16 = 9
pierwiastek(delta) = 3
x1 = (5+3)/2 = 4 = x1
x2 = (5-3)/2 = 1 = x2
x - 4/2x + 4 = x + 2 ... / *2x
2x^2 - 4 + 8x = 2x^2 + 4x
4x - 4 = 0
4x = 4
x = 1