September 2018 1 17 Report

Rozwiąż układy równań:

a){(x+3)^2-(y-`)^2=(x-y)(x+y)

3x-7y=0

b) {2x-y/4 +3x+5/2=3

x-7/5-2y+x/10=-1

w a powinno wyjść x= - 1 i 1/6 y=-1/2

w b powinno wyjsc x=0 y=-2

Z góry bardzo dziękuję =D


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