w zał
N=Ckombinacje 3 elementowe spośród 100elementów=100!/97!*3!
n=4!/2!*2! * 96!/1!*95!
P(A)=[4!/2!*2! * 96!/1!*95!] / [100!/97!*3!]
P(A)=[4*3/2 * 96] / [98*99*100/*2*3 ]
P(A)=[2*3* 96] / [98*33*50 ]
P(A)=[ 48] / [49*11*25 ]
P(A)=48/13475=0,0036
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w zał
N=Ckombinacje 3 elementowe spośród 100elementów=100!/97!*3!
n=4!/2!*2! * 96!/1!*95!
P(A)=[4!/2!*2! * 96!/1!*95!] / [100!/97!*3!]
P(A)=[4*3/2 * 96] / [98*99*100/*2*3 ]
P(A)=[2*3* 96] / [98*33*50 ]
P(A)=[ 48] / [49*11*25 ]
P(A)=48/13475=0,0036