d)(-1/2)do potegi 3
e)-(1/2)do potegi 3
c) (-1/2)do potegi 5 - 1 do potegi 4
d)(-1/2)do potęgi 3 -(-1)do potęgi 3
h)-4*(1/2)do potęgi 2
-{-0,3}do potegi 0
{ }wartość bezwzgledna
daje naj
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(-1/2)^3=(-1/2)x(-1/2)x(-1/2)=-1/8
-(1/2)^3=-(1/2)x(1/2)x(1/2)=-1/8
(-1/2)^5-1^4= (-1/32)-1=-1cala 1/32
(-1/2)^3-(-1)^3=-1/8-(-1)= 7/8
tego drugiego nie umiem poniewaz nie rozumiem
d)
e)
c)
d)
h) 1
pozdrawiam ;]