Question

WAŻNE !! Równania kwadratowe . !!!!

2x(3x+3) =0

-x (x + 1/2) =0

(2x+2) ( x-3) =0

-(3x+1)(2x-4) =0

(3x)(x)=0

(-x-2)(2-x)=0

(3+x)(1/2-2x)=0

Przykład :

2(x-1)(2x+3)=0

x-1=0 2x+3=0

x1=1 2x=-3 /:2

x=3/2 = -1 1/2

odpowiedz :

x1=1

x2=-1 1/2

Answer 1

2x (3x+3) = 0

6x² + 6x = 0

x (6x + 6) = 0

x = 0  lub  6x + 6 = 0

               x = -1

 

 

-x (x + 1/2) = 0

x (-x - 1/2) = 0

x = 0 lub -x = 1/2

              x = -1/2

 

 

(2x+2) (x-3) = 0

2x + 2 = 0  lub  x - 3 = 0

x = -1              x = 3

 

 

-(3x+1)(2x-4) = 0

(-3x-1)(2x-4) = 0

-3x-1 = 0  lub 2x - 4 = 0

x = - 1/3        x = 2

 

 

(3x)(x) = 0

6x² = 0

x = 0

 

 

(-x-2)(2-x) = 0

-x-2 = 0  lub 2-x = 0

-x = 2           -x = -2

x = -2           x = 2

 

 

(3+x)(1/2-2x) = 0

x = -3   lub   -2x = -1/2 

                   x = 1/4