Question

WAŻNE !! Równania kwadratowe . Rozwiąż tak aby 0=0 2x * (3x+3) =0 -x * (x + 1/2) =0 (2x+2) ( x-3) =0 -(3x+1)(2x-4) =0 (3x)(x)=0 (-x-2)(2-x)=0 (3+x)(1/2-2x)=0

Answer 1

2x*(3x+3) = 0

x = 0

lub

3x+3 = 0  /:3

x+1 = 0

x = -1

x = -1   v   x = 0

 

-x*(x+1/2) = 0

x = 0

lub

x+1/2 = 0

x = -1/2

x = -1/2   v   x = 0

 

(2x+2)(x-3) = 0

2x+2 = 0  /:2

x+1 = 0

x = -1

lub

x-3 = 0

x = 3

x = -1   v   x = 3

 

3x*x = 0

x = 0

 

(-x-2)(2-x) = 0

-x-2 = 0

-x = 2

x = -2

lub

2-x = 0

-x = -2

x = 2

x = -2   v   x = 2