Usuń niewymierność z mianownika:
√2 / 2√2 - 1
√5 / 2√5 - 1
√3 / 2√3 - 1
√7 / 2√7 - 1
rozwiązanie w załączniku
V2/(2V2-1) *(2V2+1)/(2V2+1) = V2(2V2+1)/(8-1) = (4+V2)/7
V5/(2V5-1) *(2V5+1)/(2V5+1) = V5(2V5+1)/(20-1) = (10+V5)/19
V3/(2V3-1) *(2V3+1)/(2V3+1) = V3(2V3+1)/(12-1) = (6+V3)/11
V7/(2V7-1) *(2V7+1)/(2V7+1) = V7(2V7+1)/(28-1) = (14+V7)/27
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rozwiązanie w załączniku
V2/(2V2-1) *(2V2+1)/(2V2+1) = V2(2V2+1)/(8-1) = (4+V2)/7
V5/(2V5-1) *(2V5+1)/(2V5+1) = V5(2V5+1)/(20-1) = (10+V5)/19
V3/(2V3-1) *(2V3+1)/(2V3+1) = V3(2V3+1)/(12-1) = (6+V3)/11
V7/(2V7-1) *(2V7+1)/(2V7+1) = V7(2V7+1)/(28-1) = (14+V7)/27