Question

[(-2)^2*(-2)^6*(-2)^3]÷[(-2)^5*(-2)^5]=?

∛64a³×b^6×c^12=?

√32÷√2

Answer 1

Answer 2

[(-2)^2*(-2)^6*(-2)^3]÷[(-2)^5*(-2)^5] = - 2^(2+6+3-5-5) =-2^1 = -2

∛64a³×b^6×c^12 = ∛[(4³a³)×b^6×c^12] = 4a×b^(6/3)×c(^12/3) = 4a×b^2×c^4

√32÷√2 = √(32/2)= √16 = 4