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1molZn-1molH2SO4-1molH2-1molZnSO4
mZn=20g
mH2SO4=28g
VH2=?
MZn=65g/mol
MH2SO4=98g/mol
65gZn---98gH2SO4
20gZn---x
x=30gH2SO4 <--z tego wynika że H2SO4 jest w niedomiarze
więc
98g H2SO4--- 22,4dm3 H2
28g H2SO4---x
x=6,4dm3 H2