Rozwiąż układyrównań
1 ) x(x+1) - y(y-1) = (x-y) ( x+y)
x + y/2 - x-y/2 = x
2) (x + 2)² - (y-3)² = (x +y)(x-y) -1
(1-x)² + (1+y)² = x(x -2) + y(y+1)
3 ) (x + 3)² + (y-2)² = x(x-1) + y(y-1)
x(x +3) + y(y+2) = (x+y)² - 2y(x-1)
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jakby co to zastosowalam wzor skroconego mnozeniia
1) x(x+1)-y(y-1)=(x-y)(x+y)
x+y/2-x-y/2=x ////+y/2 i -y/2 sie skroca
x²+x-y²-y=x²-y²
x-x=x
+x-y=x²-y²-x²+y²//////tu tez sie poskraca
x=0
0-y=0 ////////////////pod x podstawiamy 0
-y=0/*(-1)
y=0
x=0
y=0
2)(x + 2)² - (y-3)² = (x +y)(x-y) -1
(1-x)² + (1+y)² = x(x -2) + y(y+1)
x²+4x+4-y²-6y+9=x²-y²
1-2x+x²+1+2y+y²=x²-2x+y²+y
-6y=x²-y²x²-4x-4+y²
2y=x²-2x+y²+y-1+2x-x²-1-y²
-6y=-4x-4
2y=y-2
2y-y=-2
y=-2
-6 * (-2)=-4x-4
12+4=-4x/:(-4)
x=-4
y=-2
a trzecie zaraz napisze ci w wiadomosciach