Wyrażenie ma wartość : A . 3 B. 2
C.1
D.0
√3tg135°*(cos150°+sin120°)=
=√3tg(90°+45°)*[cos(180°-30°)+sin(90°+30°)]=
=√3*(-ctg45°)*[(-cos30°)+cos30°]=
=√3*(-1)*0=
=0
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
√3tg135°*(cos150°+sin120°)=
=√3tg(90°+45°)*[cos(180°-30°)+sin(90°+30°)]=
=√3*(-ctg45°)*[(-cos30°)+cos30°]=
=√3*(-1)*0=
=0