Question

Rozwiąż układ równań ( "/" = kreska ułamkowa)


2(x+3)/5 + 3(y-3)/2 = -1
3(x-1) + 4(y+1) = 5x + y

Answer 1

2x+6/5+3y-9/2=-1/*10

3x-3+4y+4=5x+y

 

4x+12+15y-45=-10

3x-5x+4y-y=3-4

 

4x+15y=-12+45-10

-2x+3y=-1

 

4x+15y=22

-2x+3y=-1/*2

 

4x+15y=22

-4x+6y=-2

      11y=22/11

 

y=2

4x+15*2=22

4x=22-30

4x=-8/4

 

x=-2

y=2

 

 

 

Answer 2

2(x+3)/5 + 3(y-3)/2 = -1/ * 5

3(x-1) + 4(y+1) = 5x + y

 

2x + 6  + 15(y-3)/2 = -5 / *2

3x - 3 + 4y + 4 = 5x + y

 

4x + 12 + 15y  - 45 = -10

3x - 5x + 4y - y = -1

 

4x + 15y = 23

-2x + 3y = -1 / :(-2)

 

4x + 15y = 23

x = 1/2 + 3/2y

 

4(1/2 + 3/2y) + 15y = 23

x = 1/2 + 3/2y

 

2 + 6y + 15y = 23

x = 1/2 + 3/2y

 

21y = 23-2

x = 1/2 + 3/2y

 

21y = 21 /:21

x = 1/2 + 3/2y

 

y = 1

x = 1/2 + 3/2

 

y = 1

x = 2