1.W ciagu arytmetycznym :a(4)=3 a(2)=7 oblicz a(20) i S(20-).
a20= a2+18r
a4=a2+2r
3=7+2r
-2r=7-3
-2r= 4 / :-2
r= -2
a20 = 7 + 18* (-2)
a20= 7- 36
a20= -29
a1= 9
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a20= a2+18r
a4=a2+2r
3=7+2r
-2r=7-3
-2r= 4 / :-2
r= -2
a20 = 7 + 18* (-2)
a20= 7- 36
a20= -29
a1= 9