1.ROZWIĄŻ RÓWNANIE
x^3+5X^2-4X-20=0
2.W CIĄGU ARYTMETYCZNYM A4=7
A6=13. OBLICZ A1,R,A10,S10.
1.:
x3 + 5x2 -4x-20=0
x(x2-4)+5(x2-4)=0\
x+5=0 lub x2-4=0
x=-5 lub x=2 lub x=-2
2. a6=a4+2r
13=7+2r
-2r=7-13
2r=6
r=3
a10=a6+4r
a10=13+4*3
a10=25
a10=a1+(10-1)3
25=a1+27
-a1=27-25
a1=-2
s10=(a1+a10)/2
s10=(-2+25)/2
s10=11,5
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1.:
x3 + 5x2 -4x-20=0
x(x2-4)+5(x2-4)=0\
x+5=0 lub x2-4=0
x=-5 lub x=2 lub x=-2
2. a6=a4+2r
13=7+2r
-2r=7-13
2r=6
r=3
a10=a6+4r
a10=13+4*3
a10=25
a10=a1+(10-1)3
25=a1+27
-a1=27-25
a1=-2
s10=(a1+a10)/2
s10=(-2+25)/2
s10=11,5