Question

A) cos 0 × cos π/6 × cos 2π/6 x cos 3π/6
b) sin π/5 × sin 2π/5 × sin 3π/5 × sin 4π/5 × sin 5π/5
c) ctg 4π/18 × ctg 5π/18 × ctg 6π/18
d) tg 3π/18 × tg 4π/18 × tg 5π/18 × tg 6π/18

Najlepiej jakby było opisane krok po kroku pokazane jak to się oblicza bo w sumie zależy mi na tym aby to zrozumieć.

Answer 1

A) cos 0 × cos π/6 × cos 2π/6 x cos 3π/6 π=180°
cos0=1
cosπ/6=cos180/60=cos30°=√3/2
cos2π/6=cosπ/3=cos180/3=cos60°=1/2
cos3π/6=cosπ/2=cos180/2=cos90₀=0

cos 0 × cos π/6 × cos 2π/6 x cos 3π/6=1*√3/2*1/2*0=0
lub
cos 0π/6 × cos π/6 × cos 2π/6 x cos 3π/6=cosπ/6(0*1*2*3)=cosπ(0)=0

b) sin π/5 × sin 2π/5 × sin 3π/5 × sin 4π/5 × sin 5π/5
sinπ/5=sin180/5=sin36°
sin2π/5=sin2*180/5=sin72°
sin3π/5=3*180/5=sin108
sin4π/180=sin4*180/5=sin144
sin5π/5=sin180

sin π/5 × sin 2π/5 × sin 3π/5 × sin 4π/5 × sin 5π/5=sin36°*sin72°*sin108*sin144*sin180=sin36°*sin36*2°*sin36*3*sin36*4*sin36*5=sin36(2*3*4*5)=sin36(120)=120sin36°

lub
sin π/5 × sin 2π/5 × sin 3π/5 × sin 4π/5 × sin 5π/5=sinπ/5(1*2*3*4*5)=sinπ*(120)=120sinπ/5=120sin180/5=120sin36°

c) ctg 4π/18 × ctg 5π/18 × ctg 6π/18=ctgπ/18(4*5*4)=ctgπ/18(120)=120ctgπ/18=120cyg180/18=120ctg10°

d) tg 3π/18 × tg 4π/18 × tg 5π/18 × tg 6π/18=
tgπ/18(3*4*5*6)=tgπ/18(360)=360tg180/10=360tg10°

Jak by co to pisz na wiadomośc