Oblicz stosujac prawa działan na potegach;)
a) (1 i2/3) do - 8 potęgi razy (0,6) do - 8 potęgi=
b) 3 do - 3 potęgi razy ( 1/9) do - 3 potęgi=
c) 6 do - 2 potęgi razy (- 1/36) do - 2 potegi=
d) 4 do - 3 potęgi razy ( 1/16) do - 3 potęgi
Prosze o odpowiedz;))
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zalacznik
a) (1⅔)⁻⁸·(0,6)⁻⁸ = (5/3)⁻⁸·(3/5)⁻⁸ = (5/3 · 3/5)⁻⁸ = 1⁻⁸ = 1
b) 3⁻³·(1/9)⁻³) = (3·1/9)⁻³ = (1/3)⁻³ = 3³ = 27
c) 6⁻²·(-1/36)⁻² = [(6·(-1/36)]⁻² = (-1/6)⁻² = (-6)² = 36
d) 4⁻³·(1/;16)⁻³ = (4·1/16)⁻³ = (1/4)⁻³ = 4³ = 64