November 2018 2 57 Report

Proszę sprawdzić czy dobrze robie i dokończyć moim sposobem !!

Zadanie.

α jest kątem rozwartym i sin α+cos α = 7/13

Oblicz tg α+ctg α

Ja zrobiłem tak:

tg\alpha +ctg\alpha=\frac{sin\alpha}{cos\alpha}+\frac{cos\alpha}{sin\alpha}=\frac{sin^{2}\alpha}{cos\alpha sin\alpha}+\frac{cos^{2}\alpha }{sin\alpha cos\alpha}=\frac{sin^{2}\alpha+cos^{2}\alpha}{sin\alpha cos\alpha}

sin\alpha+cos\alpha=\frac{7}{13}\ \ \rightarrow\ \ sin\alpha=\frac{7}{13}-cos\alpha

\frac{(\frac{7}{13}-cos\alpha)^{2}+cos^{2}\alpha}{\frac{7}{13}-cos\alpha cos\alpha}=\frac{\frac{49}{169}-\frac{14}{13}cos\alpha +cos^{2}\alpha +cos^{2}\alpha}{\frac{7}{13}-cos^{2}\alpha}=\frac{\frac{49}{169}-\frac{14}{13}cos\alpha +2cos^{2}\alpha}{\frac{7}{13}-cos^{2}\alpha}

Jak to rozwiązać dalej??


More Questions From This User See All

Recommend Questions



Life Enjoy

" Life is not a problem to be solved but a reality to be experienced! "

Get in touch

Social

© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.