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-x²+8x-16<0
-(x²-8x+16)<0
-(x-4)²<0
x=4
parabola ramionami w dół x∈R\{4}
2. 2x³-7x²+4x-14=0
x²(2x-7)+2(2x-7)=0
(2x-7)(x²+2)=0
2x-7 =0 v x²+2=0
2x=7 v x²=-2 sprzeczne
x=7/2=3,5
Rozwiazaniem jest x=3,5