1. Czy dla m = 2 liczba a jest pierwiastkiem wielomianu w?
c) w(x) = -x^3 + mx^2 - mx + 5, a = 3
d) w(x) = x^3 + 3x^2 +(m^2 -2m)x-4, a= -2
2. Rozłóż na czynniki wielomian u * w:
a) u(x) = x^3 +8x^2+16x, w(x) = x^2 - 16
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1.
c) w(x) = -x^3 + mx^2 - mx + 5
w(3) = (-3)^3 + m3^2 - m3 + 5
-27 + 9m - 3m + 5 = 0
6m = 22 / 6
m = 3,(6)
liczba m nie jest pierwiastkiem tego wielomianu
d) w(x) = x^3 + 3x^2 +(m^2 -2m)x-4
w(-2) = (-2)^3 + 3(-2)^2 + (m^2 - 2m)(-2) - 4
-8 + 12 - 2m^2 + 4m - 4 = 0
-2m^2 + 4m = 0
-2m(m - 2) = 0
m = 0 lub m = 2
liczba m jest pierwiastkiem tego wielomianu
2.
u(x) = x^3 +8x^2+16x
w(x) = x^2 - 16
x^3 + 8x^2 + 16x = 0
x(x^2 + 8x + 16) = 0
x^2 + 8x + 16
delta = 64 - 4 * 1 * 16 = 0
x0 = -8/2 = -4
x(x + 4)(x + 4) = 0
x = 0 lub x = 4
x^2 - 16 = 0
(x - 4)(x + 4) = 0
x = 4 lub x = -4